question archive Gryphin eyes can be gold (G), pink (P), or silver (S)

Gryphin eyes can be gold (G), pink (P), or silver (S)

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Gryphin eyes can be gold (G), pink (P), or silver (S). Note: letters in brackets represent the phenotype.

You cross true breeding lines of the different phenotypes to one-another, then intercross the F1s (F1 X F1) and find the following (letters represent phenotypes)

  • Cross 1 - Parental: G X S; F1 = S; F2 = 102S: 34G
  • Cross 2 - Parental: P X S; F1 = P; F2 = 117P: 39S
  • Cross 3 - Parental: P X G; F1 = P; F2 = 96P: 24S: 8G

You are not the only scientist working on gryphin genetics and while you're performing your crosses a paper is published showing that two genes are involved in gryphin eye colour.

We will call these genes A, and B. There are two alleles of each - A and aB and b.

Using the cross results above what were the parental genotypes and the genotype of the F1 for each cross (Cross 1, Cross 2 and Cross 3), above. Make sure in your answer it's clear how genotype (genes A and B) and phenotype (pink, gold, silver) are related. (6 marks)

Hint: Start with Cross 3. Review how we got a 9:7 phenotypic ratio when two genes complement each other (instead of 9:3:3:1); we calculated 7 by adding multiple categories from the Mendelian 9:3:3:1 ratio together based on how the genes were interacting -> 3 + 3+ 1 = 7. What might a 96:24:8 ratio suggest (95:25:8 = 12:3:1)? 

pur-new-sol

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There is a change in the genotype of the dihybrid cross due to dominant epistases. This is clear from the third cross ratio. In dominant epistases, a gene hides the other gene when it is dominant (homozygous dominant or heterozygous). Here the homozygous dominant or heterozygous gene A masks gene B even though gene B is dominant or heterozygous in its homozygous form. Here are the gene codes for Pink Pigment. Gene B codes for two shades of silver and gold. If the B gene is homozygous dominant or heterozygous (BB or Bb) codes for silver and in its homozygous recessive (bb) codes for gold. AABB, AABb, AAbb, AaBB, AaBb and Aabb codes for white, aaBB and aaBb codes for silver, aabb codes for gold.

So the parents of the:-

Cross 1 = abb × aaBB

Cross 2 = AABB x aaBB

Cross 3 = AABB × aabbb

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