What is the average of fixed allele if the population size is 25. What is the formula to find the answer?

And for that population size (25), what is the standard type. What is the formula?

 

1. Average of fixed allele in a particular population is given by the formula:

P = 1/(2N), where P is the probability, N is the population size = 25

therefore, average fixed allele = 1/ ( 2 x 25)

= 1/50

2. The standard type is given by the formula p² + 2pq + q² = 1, p is allele A (homozygous) while q( recessive) is allele a

therefore (1/50)² + 2(1/50)q + q² = 1

= 1/2500 + (1/25)q + q² = 1

= 1- (1/2500) = (1/25)q + q²

= 1 -0.0004 = (1/25)q + q²

= 0.9996 = (1/25)q + q²

=> 0.9996 = 0.04q + q²