question archive Assuming that p = 7 q = 11 (n == 77) then possible values for e == 91 and d =31 since the values satisfy the equation: n = p*q e*d - 1 == k*(p-1)*(q-1) for k = 1,2,3,
Subject:MathPrice:2.86 Bought3
Assuming that p = 7 q = 11 (n == 77) then possible values for e == 91 and d =31 since the values satisfy the equation:
n = p*q
e*d - 1 == k*(p-1)*(q-1) for k = 1,2,3,....
91*31 - 1 == 47*(11-1)*(7-1)
2820 == 47*10*6
Given the message m == 2 then encryption of m results in 2 since
memod n = 291 mod 77 == 2
The decryption calculation also results in 2:
2d mod n == 231 mod 77 == 2
In fact, for any message m = 2, 3, 4, 5 .. < n, the encoding of the message m using e
results in the message m and using d to decode the message again results in the original
message m
memod n == m and md mod n == m
This should not happen Explain the error :
Purchased 3 times