question archive Assuming that p = 7 q = 11 (n == 77) then possible values for e == 91 and d =31 since the values satisfy the equation: n = p*q e*d - 1 == k*(p-1)*(q-1) for k = 1,2,3,

Assuming that p = 7 q = 11 (n == 77) then possible values for e == 91 and d =31 since the values satisfy the equation: n = p*q e*d - 1 == k*(p-1)*(q-1) for k = 1,2,3,

Subject:MathPrice:2.86 Bought3

Assuming that p = 7 q = 11 (n == 77) then possible values for e == 91 and d =31 since the values satisfy the equation:

n = p*q

e*d - 1 == k*(p-1)*(q-1) for k = 1,2,3,....

91*31 - 1 == 47*(11-1)*(7-1)

2820 == 47*10*6 

Given the message m == 2 then encryption of m results in 2 since

memod n = 291 mod 77 == 2

The decryption calculation also results in 2:

2d mod n == 231 mod 77 == 2

In fact, for any message m = 2, 3, 4, 5 .. < n, the encoding of the message m using e

results in the message m and using d to decode the message again results in the original

message m 

 memod n == m and md mod n == m 

This should not happen Explain the error :

Option 1

Low Cost Option
Download this past answer in few clicks

2.86 USD

PURCHASE SOLUTION

Option 2

Custom new solution created by our subject matter experts

GET A QUOTE

rated 5 stars

Purchased 3 times

Completion Status 100%