question archive The magnetic field produced by a solenoid coil of 1393 turns of superconducting wire in a magnetic resonance imaging (MRI) system has a magnetic field strength of 2

The magnetic field produced by a solenoid coil of 1393 turns of superconducting wire in a magnetic resonance imaging (MRI) system has a magnetic field strength of 2

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The magnetic field produced by a solenoid coil of 1393 turns of superconducting wire in a magnetic resonance imaging (MRI) system has a magnetic field strength of 2.1 T. Suppose the solenoid is 1.4 m long and 5 cm in diameter. How much current is needed?

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i = 1679.525 A

Step-by-step explanation

Given that for solenoid:

number of turns N = 1393

magnetic field strength B = 2.1 T

length L = 1.4 m

diameter d = 5 cm

Let the current flowing through the solenoid be i.

Magnetic field strength inside solenoid is given by:

B = uoNi/L

i = BL/(uoN)

i = 2.1×1.4/(4π×10-7×1393)

i = 1679.525 A

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