question archive I took my three children in a park and they are playing on a seesaw of length 3

I took my three children in a park and they are playing on a seesaw of length 3

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I took my three children in a park and they are playing on a seesaw of length 3.0 m that is pivoted at its center. My child-1, mass 25 kg sat at the one edge of the seesaw and child-2, mass 20 kg sat on the other edge of the seesaw. My child-3 of mass 18 kg would like to sit somewhere in the seesaw so that all three get perfectly balanced. Find how far away from the pivot point my third child must be sitting? Mass of seesaw is negligibly small compared to mass of my children. 

 

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Moment about pivot should be balanced.

25×9.81×1.5-18.x.(9.81)-20×9.81×1.5=0

Solve for x,

x=0.4167 m from the pivot and on the side of 20 kg child.

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