question archive The results of the blood pressure of ten subjects before and after the six week treatment are given in the following list: (73,73), (83,79), (85,81), (87,86), (91,87), (99,91), (87,84), (85,83), (83,84), (79,76) Is this an evidence of effectiveness of the treatment? Test the hypothesis at 95% level with the paired sample design using the differences: 0 1 : 0; : 0
The results of the blood pressure of ten subjects before and after the six week treatment are given in the following list: (73,73), (83,79), (85,81), (87,86), (91,87), (99,91), (87,84), (85,83), (83,84), (79,76) Is this an evidence of effectiveness of the treatment? Test the hypothesis at 95% level with the paired sample design using the differences: 0 1 : 0; : 0
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The results of the blood pressure of ten subjects before and after the six week treatment are given in the following list: (73,73), (83,79), (85,81), (87,86), (91,87), (99,91), (87,84), (85,83), (83,84), (79,76) Is this an evidence of effectiveness of the treatment? Test the hypothesis at 95% level with the paired sample design using the differences: 0 1 : 0; : 0. H H d d (Use the difference before-after).
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Difference Scores Calculations
Mean: -2.8
μ = 0
S2 = SS⁄df = 57.6/(10-1) = 6.4
S2M = S2/N = 6.4/10 = 0.64
SM = √S2M = √0.64 = 0.8
T-value Calculation
t = (M - μ)/SM
= (-2.8 - 0)/0.8
= -3.5
Therefore,
The value of test statistic is = -3.5
Corresponding p-value = 0.00672 {From standard t-table, available on internet}
Please see the attached file for the complete solution
