question archive If a proton is accelerated from rest through a potential difference of 1,250 V, find its approximate velocity at the end of this process
If a proton is accelerated from rest through a potential difference of 1,250 V, find its approximate velocity at the end of this process
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If a proton is accelerated from rest through a potential difference of 1,250 V, find its approximate velocity at the end of this process.
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KE = qV = (1.602x10^-19)(1250) = 2*10^-16 J
KE = mv^2 / 2
v= √(2KE/m)
= √(2*2*10^-16/1.673*10^-27)
= 488970 m/s
