What volume of 0.22 M H₂SO₄ can be prepared by diluting 131 mL of 5.3 M H₂SO₄?

The volume of 0.22 M H₂SO₄ can be calculated by using the required formula -

M₁ × V₁ = M₂ × V₂

where,

M₁ = Initial concentration

V₁ = Initial volume

M₂ = Final concentration

V₂ = Final volume

Here,

M₁ = 5.3 M

V₁ = 131 mL

Now let us convert the volume into litres -

1 L = 1000 mL

131 mL = (131 / 1000) L = 0.131 L

V₁ = 0.131 L

M₂ = 0.22 M

V₂ = ?

Now let us substitute the values in the above formula -

M₁ × V₁ = M₂ × V₂

5.3 M × 0.131 L = 0.22 M × V₂

V₂ = ( 5.3 M × 0.131 L ) / 0.22 M

V₂ = 3.16 L

Thus, the final volume is 3.16 L