question archive Question 11  You have a stock solution of 2

Question 11  You have a stock solution of 2

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Question 11 

You have a stock solution of 2.00 mol/L potassium iodide, KI(aq). What volume of the stock solution do you need to prepare each of the following solutions?SHOW CALCULATIONS PLEASE.

a) 50.0 mL of 1.00 mol/L

b) 150.0 mL of 0.500 mol/L

Question 12 

A pharmaceutical assistant has a 50.0 g/L solution of glucose, C6H12O6(aq).

a) What is the concentration of the solution in mol/L? 

b) What volume of the glucose solution should the pharmaceutical assistant use to make 500.0 mL of a 0.050 mol/L glucose solution?

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Question 11 

You have a stock solution of 2.00 mol/L potassium iodide, KI(aq). What volume of the stock solution do you need to prepare each of the following solutions?SHOW CALCULATIONS PLEASE.

a) 50.0 mL of 1.00 mol/L

C1V1 = C2V2 where:

V1 = Volume of stock solution needed to make the new solution

C1 = Concentration of stock solution

V2 = Final volume of new solution

C2 = Final concentration of new solution

 

C1=2.00 mol/L

V1 = X

 C2= 1.00 mol/L

V2= 50.0 mL

2.00 mol/L × X = 1.00 mol/L ×50.0 mL

X =(1.00 mol/L ×50.0 mL) ÷ 2.00 mol/L

= 25.0 mL

 

b) 150.0 mL of 0.500 mol/L

 

C1=2.00 mol/L

V1 = X

 C2= 0.500 mol/L

V2= 150.0 mL

2.00 mol/L × X = 0.500 mol/L ×150.0 mL

X =(0.500 mol/L ×150.0 mL) ÷ 2.00 mol/L

= 37.5 mL

Question 12 

A pharmaceutical assistant has a 50.0 g/L solution of glucose, C6H12O6(aq).

a) What is the concentration of the solution in mol/L? 

 

Start by converting grams per litre into moles per litre.

Molar mass of glucose = 180.156 g/mol

Moles of glucose present in a litre solution = mass present/molar mass

=50.0 g ÷ 180.156 g

= 0.278 moles/L

 

b) What volume of the glucose solution should the pharmaceutical assistant use to make 500.0 mL of a 0.050 mol/L glucose solution?

 

C1V1 = C2V2

C1= 0.278 moles/L

V1 = X

 C2= 0.050 mol/L

V2= 500.0 mL

0.278 moles/L × X = 0.050 mol/L × 500.0 mL

X =(0.050 mol/L × 500.0 mL) ÷ 0.278 moles/L

= 89.9 mL

To make a fixed amount of a dilute solution from a stock solution, you can use the formula: C1V1 = C2V2 where:

V1 = Volume of stock solution needed to make the new solution

C1 = Concentration of stock solution

V2 = Final volume of new solution

C2 = Final concentration of new solution