14) A pendulum oscillates at its natural frequency of 2 Hz on earth, what frequency would the same pendulum
oscillate on the Mars (gmars = 3.7 N/kg)?

 

Length of pendulum be l

Natural frequency of pendulum, f_n= 2 Hz

Acceleration due to gravity on earth, g_n= 9.8 N/kg

now,

Let frequency of pendulum on Mars be, f_m= ?

Acceleration due to gravity on Mars, g_m= 3.7 N/kg

Now, frequency of pendulum= (1/2?π?)* sqrt(g/l)

Hence, on dividing frequencies on earth and mars, we get

f_n/f_m= sqrt(g_n/g_m)

2/f_m= sqrt(9.8/3.7)

2/f_m= 1.6275

f_m= 1.2288 Hz