question archive For the f:z->z defined by f(n)=[n/3]
For the f:z->z defined by f(n)=[n/3]
Subject:MathPrice:2.86 Bought3
For the f:z->z defined by f(n)=[n/3]. Show that f is surjective but f is not injective
question archive For the f:z->z defined by f(n)=[n/3]
Subject:MathPrice:2.86 Bought3
For the f:z->z defined by f(n)=[n/3]. Show that f is surjective but f is not injective
