question archive The reaction below has an equilibrium constant Kp=2
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The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)?CO2(g)+CF4(g)
1. Calculate Kp for the reaction below.
COF2(g)?12CO2(g)+12CF4(g)
Express your answer using two significant figures.
2. Calculate Kp for the reaction below.
23COF2(g)?13CO2(g)+13CF4(g)
Express your answer using two significant figures.
The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)?CO2(g)+CF4(g)
1)Calculate Kp for the reaction below.
COF2(g)?1/2CO2(g)+1/2CF4(g)
Solution :-
Original equation is divided by 2 to get the new equation therefore the to find the kp for the new equation we need to take the square root of the orginal kp
Therefore
Kp = square root of (2.2*10^6)
Kp = 1.5*10^3
2. Calculate Kp for the reaction below.
2/3COF2(g)?1/3CO2(g)+1/3CF4(g)
Solution :- Here orginal equation is divided by 3
Therefore to calculate kp for this equation we need to take the cube root of the original kp
Hence
Kp = cube root (2.2*10^6)
Kp = 1.3*10^2