question archive The reaction below has an equilibrium constant Kp=2

The reaction below has an equilibrium constant Kp=2

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The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)?CO2(g)+CF4(g)

1. Calculate Kp for the reaction below.
COF2(g)?12CO2(g)+12CF4(g)

Express your answer using two significant figures.

2. Calculate Kp for the reaction below.

23COF2(g)?13CO2(g)+13CF4(g)

Express your answer using two significant figures.

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The reaction below has an equilibrium constant Kp=2.2×106 at 298 K.
2COF2(g)?CO2(g)+CF4(g)

1)Calculate Kp for the reaction below.
COF2(g)?1/2CO2(g)+1/2CF4(g)

Solution :-

Original equation is divided by 2 to get the new equation therefore the to find the kp for the new equation we need to take the square root of the orginal kp

Therefore

Kp = square root of (2.2*10^6)

Kp = 1.5*10^3

2. Calculate Kp for the reaction below.

2/3COF2(g)?1/3CO2(g)+1/3CF4(g)

Solution :- Here orginal equation is divided by 3

Therefore to calculate kp for this equation we need to take the cube root of the original kp

Hence

Kp = cube root (2.2*10^6)

Kp = 1.3*10^2