question archive A physics student drives a car of total mass of 950 kg and velocity of 25 m/s she sees a SpeedZone Ahead in slows down to a new velocity of 17 m/s in a time of 3
A physics student drives a car of total mass of 950 kg and velocity of 25 m/s she sees a SpeedZone Ahead in slows down to a new velocity of 17 m/s in a time of 3
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- A physics student drives a car of total mass of 950 kg and velocity of 25 m/s she sees a SpeedZone Ahead in slows down to a new velocity of 17 m/s in a time of 3.2 seconds
a.)determined the original momentum up the car
b.)what impulse was applied to the car c.) calculate the size of force acting on the car
- 45 kg cart travelling at 24 m/s collides with the stationary 28 kg cart after the collision 45 kg cart continues forward with the speed of 12 m/s
a.) what is the speed of the 28 kg cart after the collision
b.) calculate the impulse delivered to the 45 kg cart
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- Mass of car, m= 950 kg
initial velocity, u= 25 m/s
final velocity, v= 17 m/s
time, t= 3.2 s
a) Original Momentum of car, p= mu
p =950*25
p =23,750 kg.m/s
b) Impulse= Change in momentum
Impulse= m(v-u)
Impulse= 950 (17-25)
Impulse= 950*(-8)
Impulse= 7600 kg.m/s or Ns
c) Force= impulse/time
Force= 7600/ 3.2
Force= 2375 Newton
- Mass of cart 1 , m1= 45 kg
initial velocity of cart 1, u1= 24 m/s
Mass of cart 2 , m2= 28 kg
initial velocity of cart 2, u2= 0 m/s
final velocity of cart 1, v1= 12 m/s
final velocity of cart 2, v2= ?
a) As per Conservation of momentum,
m1u1+ m2u2= m1v1+ m2v2
45*24 + 28*0 = 45*12 + 28* v2
1080= 540 + 28* v2
540= 28* v2
v2= 30 m/s (final velocity of cart 2)
(b) Impulse to cart 1
Impulse= Change in momentum
Impulse= m1(v1-u1)
Impulse= 45(12-24)
Impulse= 45*(-12)
Impulse= -540 kg. m/s
