question archive A roller coaster cart of mass m = 379 kg starts stationary at point A, where h1 = 21 m and a while later is at B, where h2 = 7
A roller coaster cart of mass m = 379 kg starts stationary at point A, where h1 = 21 m and a while later is at B, where h2 = 7
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A roller coaster cart of mass m = 379 kg starts stationary at point A, where h1 = 21 m and a while later is at B, where h2 = 7.6 m. The acceleration of gravity is 9.8 m/s 2 .
What is the potential energy of the cart relative to the ground at A? Answer in units of J.
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Given the following data
Mass of the roller coaster cart m = 379 kg
At point A height h1 = 21 m
The acceleration of gravity is 9.8 m/s 2 .
What is the potential energy of the cart relative to the ground at A?
Solution
Formula
P.E = mgh
Where P.E is potential energy of the cart relative to the ground at A
m is the mass of the roller coaster cart m = 379 kg
The acceleration of gravity = 9.8 m/s2
h is the height at point A h1 = 21 m
P.E = mgh
P.E = (379 kg)(9.8 m/s2)(21 m )
P.E = 77998.2 J
The potential energy of the cart relative to the ground at A P.E = 77998.2 J
