question archive The Sun orbits the center of the Galaxy in 225 million years at a distance of 26,000 light-years
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The Sun orbits the center of the Galaxy in 225 million years at a distance of 26,000 light-years. Given that a 3 = (M1 + M2 ) × P 2 , where a is the semimajor axis and P is the orbital period, what is the mass of the Galaxy within the Sun's orbit?
a3 = (m1 + m2) P2
in this formula
a is the semimajor axis in AU,
P is the orbital period in Earth years, and
m is mass of object in relation to Sun's mass M?
Thus, we have to cenvert the given
1 ly = 9.46 x 1015 m
1 AU = 1.5 x 1011 m
a = 26000 ly (9.46 x 1015 m / 1 ly )(1 Au / 1.5 x 1011 m)
a = 1.64 x 10^9 Au
a3 = (msun + mgalaxy) P2
(a3 / P2) = (msun + mgalaxy)
since msun = 1 M? and is a very small fraction of mgalaxy the formula can be
mgalaxy = (a3 / P2)
mgalaxy = (1.64 x 109)3 / (225 x 106)2
mgalaxy = 8.7810 M?