question archive The Sun orbits the center of the Galaxy in 225 million years at a distance of 26,000 light-years

The Sun orbits the center of the Galaxy in 225 million years at a distance of 26,000 light-years

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The Sun orbits the center of the Galaxy in 225 million years at a distance of 26,000 light-years. Given that a 3 = (M1 + M2 ) × P 2 , where a is the semimajor axis and P is the orbital period, what is the mass of the Galaxy within the Sun's orbit?

 

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a3 = (m1 + m2) P2

 

in this formula

a is the semimajor axis in AU,

P is the orbital period in Earth years, and

m is mass of object in relation to Sun's mass M?

 

Thus, we have to cenvert the given

1 ly = 9.46 x 1015 m

1 AU = 1.5 x 1011 m

 

a = 26000 ly (9.46 x 1015 m / 1 ly )(1 Au / 1.5 x 1011 m)

a = 1.64 x 10^9 Au

 

a3 = (msun + mgalaxy) P2

 

(a3 / P2) = (msun + mgalaxy)

 

since msun = 1 M? and is a very small fraction of mgalaxy the formula can be

 

mgalaxy = (a3 / P2)

mgalaxy = (1.64 x 109)3 / (225 x 106)2

 

mgalaxy = 8.7810 M?