question archive Can a person outrun a Hualalai lava flow if you are out of shape and can only walk 16 kilometers per hour (3

Can a person outrun a Hualalai lava flow if you are out of shape and can only walk 16 kilometers per hour (3

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Can a person outrun a Hualalai lava flow if you are out of shape and can only walk 16 kilometers per hour (3.73 miles per hour) and a wide lava flow (too wide to head to the side) is heading towards you at 28 km/hour (17.4 mph)? or, how long will it be before the lava flow overtakes this person?

           Assume that the person has a 2 kilometer head start when s/he gets notice that the lava is heading towards them.

           Select the answer that is closest to what you calculate.

 

Group of answer choices

 

 

A.) 5 minutes

 

B.) 20 minutes

 

C.)10 minutes

 

d.)15 minutes

 

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C.)10 minutes

Step-by-step explanation

The speed of the person is 16 km per hour or 0.267 km per minute. The speed of lava is given as 28 km per hour or 0.4667 km per minute. The person has already walked 2 km distance before noticing the lava.

Speed is equal to distance divided by time (speed = d/t)

 

After 10 minutes, the distance covered by the person would be:

d = speed x time

d = 0.267 km/minute x 10 minutes

d = 2.67 km

Since the person is 2km ahead, he would be 4.67 km away (2 km + 2.67 km) from the lava.

 

After 10 minutes, the distance covered by the relatively faster lava would be:

d = speed x time

d = 0.487 km/minute x 10 minutes

d= 4.67 km

 

After 10 minutes, the lava would have traveled 4.67 km which is the position of the person.