question archive In a random sample of 62 individuals, we found that their average weekly income level is 1900 with a standard deviation of 660
In a random sample of 62 individuals, we found that their average weekly income level is 1900 with a standard deviation of 660
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In a random sample of 62 individuals, we found that their average weekly income level is 1900 with a standard deviation of 660. What is the standard of error of the sample mean?
Round the intermediate numbers to 4 decimal places
Round the final answer to 3 decimal places. Have the final answer in 3 decimal places
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The standard error is computed through the formula;
S.E = σ/√n
Where σ is the standard deviation and n is the sample size
So we have;
S.E = 660/√62
= 83.820
