question archive Suppose a survey of 240 college students finds that 147 say they are not getting enough sleep construct a 95% confidence interval for the proportions of college students who are not getting enough sleep what is the upper end of the confidence interval answer as a decimal round at least 3 decimals
Suppose a survey of 240 college students finds that 147 say they are not getting enough sleep construct a 95% confidence interval for the proportions of college students who are not getting enough sleep what is the upper end of the confidence interval answer as a decimal round at least 3 decimals
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Suppose a survey of 240 college students finds that 147 say they are not getting enough sleep construct a 95% confidence interval for the proportions of college students who are not getting enough sleep
what is the upper end of the confidence interval answer as a decimal round at least 3 decimals
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Sample population; p = 147 / 240 = 0.6125
Sample size; n = 240
95% confidence interval; CI = p +- Z * Sqrt( p * (1 - p) / n)
Lower bound = 0.6125 - 1.96 * Sqrt( 0.6125 * (1 - 0.6125) / 240) = 0.550863304 = 0.551
Upper bound = 0.6125 + 1.96 * Sqrt( 0.6125 * (1 - 0.6125) / 240) = 0.674136696 = 0.674
upper end of the confidence interval is 0.67
