1) which of the following has the greatest ionic radius? Mg2+ Mg Mg- Mg+ Mg2-

2)which answer choice shows the atoms/ions in order from most easily to least easily oxidized? 

Group of answer choices

Si, Ca, O, Cu, Cs

Si, O, Cu, Cs, Ca

O, Si, Cu, Ca, Cs

Cs, Ca, Cu, Si, O

Ca, Cs, Cu, Si, O

3)Which of the following electron configurations is/are an excited state atom? choose all that apply.

Group of answer choices

1s22s22p63s23p63d5

1s22s22p63s23p3

1s22s22p63s23p64s25p1

1s22s22p63s23p64s13d6

1s22s22p63s23p64s23d1

1s22s22p63s23p5

4)The following is the electron configuration of what atom/ion? choose all that apply.

1s22s22p63s23p4

Group of answer choices

P-

Ar

Cl-

S

P+

Cl+

5)Which of the following transitions absorbs energy having the highest frequency?

Group of answer choices

n=5 to n=1

n=2 to n=5

n=10 to n=11

n=4 to n=1

n=2 to n=3

n=5 to n=8

6)Which of the following transitions absorbs energy having the shortest wavelength?

Group of answer choices

n=2 to n=5

n=5 to n=1

n=5 to n=8

n=10 to n=11

n=4 to n=1

n=2 to n=3

1) The greatest ionic radius => ?Mg2−? [anions will always have the higher ionic radius, higher the negative charge larger is the radius]

2) order from most easily to least easily oxidized => Cs, Ca, Cu, Si, O [higher the electronegativity less easily it can be oxidized]

3) excited state atoms:

• 1s22s22p63s23p63d5 [only in excited state the 3d orbital will fill directly after 3p ]
• 1s22s22p63s23p64s25p1 [only in excited state the 5p orbital will fill directly after 4s]
• 1s22s22p63s23p64s13d6 [in excited state only, 1 electron from 4s orbital moves to 3d orbital (normally the configuration should be 4s23d5)]

4) the following is the electronic configuration of :

• P-
• S
• Cl+

5) transitions absorbs energy having the highest frequency => n=2 to n=5

explanation: energy is absorbed when transition is happening from a lower state (n = low) to a higher state (n = high), now larger the difference between the two "n" values higher will be the frequency, so you have to options 1. n = 2 to n = 5 & 2. n = 5 to n = 8, now another factor comes, lower the range of n values higher will be the frequency, thus the correct option is 1. n =2 to n =5 as

energy difference ?∝? frequency ?∝? ?(n12?1?−n22?1?)?

where ?n1?? = lower energy state = 2

?n2?? = higher energy state = 5

6) transitions absorbs energy having the shortest wavelength => n=10 to n=11

here the conditions are just reversed from the previous question, since they are asking for shortest wavelength, we have to find the lowest difference of the "n" values, and very high individual "n" values

and that is the case for n = 10 to n = 11

energy difference ?∝? frequency ?∝??(n12?1?−n22?1?)?

here ?n1?? = lower energy state = 10

?n2?? = higher energy state = 11 {see how the value of individual "n" values are very high and the difference between them = 11 - 10 = 1 , very small}