question archive Fifty percent of households say they would feel secure if they had? $50,000 in savings
Subject:StatisticsPrice:2.86 Bought8
Fifty percent of households say they would feel secure if they had? $50,000 in savings. You randomly select 8 households and ask them if they would feel secure if they had? $50,000 in savings. Find the probability that the number that say they would feel secure is? (a) exactly? five, (b) more than? five, and? (c) at most five.
a)= 0.21875
(or ans =0.2188 if round 4 decimal)
b) 0.14453125
(if round 4 decimal places then
ans =0.1445)
c) 0.85546875
(if round 4 decimal places then
ans = 0.8555)
Step-by-step explanation
It is case of Binomial distribution
Probability mass function of Binomial distribution -
P(X=r)= ?(rn?)prqn−r?
where
?(rn?)=(n−r)!r!n!??
Here
n= 8
probability of success
p=50%= 0.50
q= 1-p= 1-0.50= 0.5
a)
Need to find
P(X=5)= ?(58?)(0.50)5(0.50)8−5?
as
?(58?)=(8−5)!5!8!?=5!×3×2×18×7××6×5!?? = 56
so
P(X=5)= (56)(0.50)?5(0.50)3?
= 0.21875
(or it is =0.2188 if round 4 decimal)
b) more than 5
need to find
P(X>5)= P(X=6)+P(X=7)+P(X=8)
now
P(X=6)= ?(68?)(0.50)6(0.50)2?
as
?(68?)=(8−6)!6!8!?=6!×2×18×7×6!?? =,28
so
P(X=6)=(28)(0.5)?6(0.50)2?
=0.109375
similarly
P(X=7)= ?(78?)(0.5)7(0.5)1?
=(8)(0.5)?7(0.5)? = 0.03125
P(X=8)= ?88?(0.50)8(0.50)0?
=(1)(0.50)?8? = 0.00390625
so
P(X>5)= 0.109375+0.03125+
0.00390625
=0.14453125
or
=0.1445 (if round 4 decimal)
c) at most 5
neeed to find
P(X?≤? 5) =1-P(X>5)
As
P(X>5)= 0.14453125 (as done above)
so
P(X?≤? 5)= 1-0.14453125
= 0.85546875
or
= 0.8555 (if round 4 decimal)