question archive Given the reaction: 4Al + 3O2 ® 2Al2O3 What is the total number of moles of aluminum oxide (Al2O3) that can be formed when 54 grams of aluminum (Al) reacts completely with oxygen? (a) 1
Given the reaction: 4Al + 3O2 ® 2Al2O3 What is the total number of moles of aluminum oxide (Al2O3) that can be formed when 54 grams of aluminum (Al) reacts completely with oxygen? (a) 1
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Given the reaction: 4Al + 3O2 ® 2Al2O3
What is the total number of moles of aluminum oxide (Al2O3) that can be formed when 54 grams of aluminum (Al) reacts completely with oxygen?
(a) 1.0 moles
(b) 2.0 moles
(c) 3.0 moles
(d) 4.0 moles
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Correct answer is
A. 1 mole.
4Al + 3O2 ---- 2 Al2O3.
Mole of Al used=
Moles = mass(g)/ molar mass.
Moles = 54 g/ 27g/mole.
Moles of aluminum is 2 moles.
Mole ratio of Al to Al2O3 is 4:2= 2:1
For every mole of Al used, 1 mole of Al2O3 is formed.
So if 2 moles of Al was used, moles of Al2O3 formed = 2 moles÷2 = 1 mole.
