question archive If P° and Ps are vapous pressure of solvent so in repulsively n1 and n2 are molefractions of solve and solule respecliuely then a) Ps = P°n1    b) Ps = P°n2       c) P° = Psn2         d) Ps = P°(n1/n2) from Roulles law

If P° and Ps are vapous pressure of solvent so in repulsively n1 and n2 are molefractions of solve and solule respecliuely then a) Ps = P°n1    b) Ps = P°n2       c) P° = Psn2         d) Ps = P°(n1/n2) from Roulles law

Subject:ChemistryPrice:0 Bought3

If P° and Ps are vapous pressure of solvent so in repulsively n1 and n2 are molefractions of solve and solule respecliuely then

a) Ps = P°n1    b) Ps = P°n2       c) P° = Psn2         d) Ps = P°(n1/n2)

from Roulles law.

P° - Ps/P0 = n2              1 – Ps/P0 = n2

Ps/P0 = 1 – n2 = n

Ps = n1*P°   

pur-new-sol

Purchase A New Answer

Custom new solution created by our subject matter experts

GET A QUOTE