question archive The average amount of a beverage in randomly selected 16-ounce beverage can is 16
The average amount of a beverage in randomly selected 16-ounce beverage can is 16
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The average amount of a beverage in randomly selected 16-ounce beverage can is 16.1 ounces with a standard deviation of 0.3 ounces. If a random sample of sixty-four 16-ounce beverage cans are selected, what is the probability that the mean of this sample is less than 16.2 ounces of beverage? Answer: (keep 4 decimal places)
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Answer:
Required probability is 0.9962
Step-by-step explanation
Formula to find the probability is
P(X<x) = NORMSDIST(x,mean,standard deviation,CUMULATIVE)
where x = 16.2
mean = 16
standard deviation = 0.3/SQRT(64)
CUMULATIVE = TRUE (for less than case)
?→P(X?<16.2)=NORMDIST(16.2,16,1,0.3/SQRT(64),TRUE)=0.9962?
