question archive After driving a portion of the route, the taptap is fully loaded with a total of26people including the driver, with an average mass of64kg per person

After driving a portion of the route, the taptap is fully loaded with a total of26people including the driver, with an average mass of64kg per person

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After driving a portion of the route, the taptap is fully loaded with a total of26people including the driver, with an average mass of64kg per person. In addition, there are three 15-kg goats, five 3-kg chickens, and a total of 25 kg of bananas on their way to the market. Assume that the springs have somehow not yet compressed to their maximum amount. How much are the springs compressed?

 

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We know,

Force = kx= mg

m= total mass

 

So , x = [(26×64)+ (3×15) + (5×3) + 25] ×9.8 / k

x = 1749 ×9.8 /k

 

Therefore , x= 17140.2/ k meters

 

If the value of k is provided we can find the final ans

If k is 4×10^4 N/m then ,

x = 0.428 m