question archive A candle (ho = 0
A candle (ho = 0
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A candle (ho = 0.39 m) is placed to the left of a diverging lens (f = -0.054 m). The candle is do = 0.34 m to the left of the lens.
ho = 0.39 m
f = -0.054 m
do = 0.34 m
Part (a) Write an expression for the image distance, di.
Part (b) Numerically, what is the image distance in meters?
Part (c) Is this real or virtual?
Part (d) Numerically, what is the image height, hi?
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a) 1/do + 1/di = 1/f
1/di = 1/f - 1/do
di = (do*f)/(do-f)
b) di = -0.34*0.054/(0.34+0.054) = -0.047 m
c)No. the image is virtual
d) m = -di/do = 0.047/0.34 = 0.137
hi = m*ho
= 0.137*0.39
= 0.053 m
