The value of Ka for nitrous acid (HNO2) at 25 ?C is 4

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The value of Ka for nitrous acid (HNO2) at 25 ?C is 4.5×10−4 .

a. Write the chemical equation for the equilibrium that corresponds to Ka

1. H+(aq)+NO−2(aq)?HNO2(aq)

2. HNO2(aq)?H+(aq)+NO−2(aq)

3. HNO2(aq)?H−(aq)+NO+2(aq)

4. HNO2(aq)+H+(aq)?H2NO+2(aq)

5. HNO2(aq)+H−(aq)?H2NO+2(aq)

?b. By using the value of Ka , calculate ΔG? for the dissociation of nitrous acid in aqueous solution.  

c. What is the value of ΔG at equilibrium?        

d. What is the value of ΔG when [H+] = 5.9×10⁻² M , [NO−2] = 6.7×10⁻⁴ M , and [HNO2] = 0.21 M ?