question archive The value of Ka for nitrous acid (HNO2) at 25 ?C is 4
The value of Ka for nitrous acid (HNO2) at 25 ?C is 4
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The value of Ka for nitrous acid (HNO2) at 25 ?C is 4.5×10−4 .
a. Write the chemical equation for the equilibrium that corresponds to Ka
| 1. H+(aq)+NO−2(aq)?HNO2(aq) |
| 2. HNO2(aq)?H+(aq)+NO−2(aq) |
| 3. HNO2(aq)?H−(aq)+NO+2(aq) |
| 4. HNO2(aq)+H+(aq)?H2NO+2(aq) |
| 5. HNO2(aq)+H−(aq)?H2NO+2(aq) |
?b. By using the value of Ka , calculate ΔG? for the dissociation of nitrous acid in aqueous solution.
c. What is the value of ΔG at equilibrium?
d. What is the value of ΔG when [H+] = 5.9×10−2 M , [NO−2] = 6.7×10−4 M , and [HNO2] = 0.21 M ?
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