question archive On a frictionless horizontal air table, puck A (with mass 0

On a frictionless horizontal air table, puck A (with mass 0

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On a frictionless horizontal air table, puck A (with mass 0.249kg ) is moving toward puck B (with mass 0.371kg ), which is initially at rest. After the collision, puck A has velocity 0.123m/s to the left, and puck B has velocity 0.646m/s to the right. A)What was the speed Vai of puck A before the collision. B)Calculate , the change in the total kinetic energy of the system that occurs during the collision.

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Ma*Va=Ma*Va2+Mb*Vb here Va2=-0.123 i and Vb=0.646 i this gives Va=0.8395 m/s and change in K.E is ---->0.5[(Ma*Va^2)-(Ma*Va2^2+Mb*Vb^2)]=0.087774-0.07929=0.008449 J