question archive Calculate the molar solubility of PbCl2 in pure water, Ksp for PbCl2 is 1
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Calculate the molar solubility of PbCl2 in pure water, Ksp for PbCl2 is 1.17 x 10^-5.

Answer:
the dissociation of PbCl2 is as follows:
Let the solubility as S
PbCl2(s) <======> Pb2+ + 2Cl-
S S 2S
Ksp = [Pb2+][Cl-]2
Ksp = [S][2S]2
Ksp = 4S3
S = (Ksp/4)1/3
S = (1.17*10-5)1/3
S = 0.0143 M
Hence, molar solubility is 0.0143 M.

