question archive In preparing calibration standards, a stock solution is typically first prepared, then diluted to different concentrations to produce a series of standards

In preparing calibration standards, a stock solution is typically first prepared, then diluted to different concentrations to produce a series of standards

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In preparing calibration standards, a stock solution is typically first prepared, then diluted to different concentrations to produce a series of standards. For the analysis of SO2, standards at 5, 10, 25, 50, and 100 mg/L SO2 are required. Describe a procedure to first prepare 100 mL of stock solution (1000 mg/L SO2) using solid potassium metabisulfite salt K2S2O5. Then describe how dilutions would be done to produce 100 mL each of the remaining solutions (5, 10, 25, 50 and 100 mg/L) using the 4000 mg/L stock.

  • K2S2O5 has a molecular mass of 222.31 g/mol and yields 2 mole SO2 per mole of K2S2O5
  • K2S2O5 + H20 -> 2 SO2 + 2 KOH

 

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Preparation of Stock Solution (1000 mg/L SO2)

Stock Solution: 100 mL or 0.1 L of 1000 mg / L SO2 concentration

Amount of SO2 in 100 mL stock solution = 0.1 L x (1000 mg SO2 / 1 L solution) = 100 mg SO2

 

Therefore, in your 100 mL stock solution, 100 mg of SO2 is present.

Now, you need to find the amount of K2S2O5 that you need to make 100 mg of SO2.

 

Using the equation and the given values (I searched the mol. mass of SO2 myself since it's not given):

K2S2O5 + H2O --> 2SO2 + 2KOH

 

Mol. Mass SO2 = 64.07 g/mol

Mol. Mass K2S2O5 = 222.31 g/mol

100 mg SO2 = 0.1 g SO2

 

Amount of K2S2O5 needed = 0.1 g SO2 x (1 mol SO2 / 64.07 g SO2) x (1 mol K2S2O5 / 2 mol SO2) x (222.31 g K2S2O5 / 1 mol K2S2O5)

Amount of K2S2O5 needed = 0.1735 g or 17.35 mg K2S2O5

 

The stock solution can then be prepared as follows:

Accurately weigh 17.35 mg of K2S2O5 and dilute it to 100 mL using distilled water

------------------------------

 

Preparation of other Standards:

To determine the volume needed to make the lower concentration standards, we need to use the dilution formula:

 

C1V1 = C2V2, where:

C1 = Stock concentration = 1000 mg/L

V1 = Volume of stock needed

C2 = Final or Target Concentration = 5, 10, 25, 50 and 100 mg/L

V2 = Volume of target solution = 100 mL = 0.1 L

 

Final formula:

V1 = C2V2 / C1

 

Let's solve them one by one:

a) 5 mg/L

V1 = C2V2 / C1

V1 = (5 mg/L x 0.1 L) / 1000 mg/L

V1 = 0.0005 L or 0.5 mL

 

Preparation:

Measure 0.5 mL of stock solution (1000 mg/L) and transfer it into a 100 mL volumetric flask. Fill to mark with distilled water to prepare 5 mg/L

Use the same approach for the next concentrations:

 

b) 10 mg/L

V1 = C2V2 / C1

V1 = (10 mg/L x 0.1 L) / 1000 mg/L

V1 = 0.001 L or 1 mL

 

c) 25 mg/L

V1 = C2V2 / C1

V1 = (25 mg/L x 0.1 L) / 1000 mg/L

V1 = 0.0025 L or 2.5 mL

 

d) 50 mg/L

V1 = C2V2 / C1

V1 = (50 mg/L x 0.1 L) / 1000 mg/L

V1 = 0.005 L or 5 mL

 

e) 100 mg/L

V1 = C2V2 / C1

V1 = (100 mg/L x 0.1 L) / 1000 mg/L

V1 = 0.01 L or 10 mL

 

I made a summary of the preparation for the standard solutions below :)

Please see the attached file for the complete solution