question archive lets assume females have pulse rates that are normally distributed with a mean of μ=76 beats per minute and a standard deviation of σ=12

lets assume females have pulse rates that are normally distributed with a mean of μ=76 beats per minute and a standard deviation of σ=12

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lets assume females have pulse rates that are normally distributed with a mean of μ=76 beats per minute and a standard deviation of σ=12.5 beats per minute.

If 1 adult female is randomly? selected, how would i find the probability that her pulse rate is less than 82, rounded to 4 decimal places if necessary?

pur-new-sol

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answer = 0.6844

Step-by-step explanation

we have that  μ=76 and σ=12.5

z =?σx−μ??

Hence

P(x < 82) = P(z <?12.582−76?? )

=P(z < 0.48)

Now fro z table, we check the probability that correspond to z = 0.48

= 0.6844

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