question archive 3) A 2-kg point-like (cannot rotate) object interacts with an unknown source and the potential energy (P E) as a function of horizontal coordinate (x in meters) is given by the equation P E(x) = 1 4x4 6x3 + 46x2 120x
3) A 2-kg point-like (cannot rotate) object interacts with an unknown source and the potential energy (P E) as a function of horizontal coordinate (x in meters) is given by the equation P E(x) = 1 4x4 6x3 + 46x2 120x
Subject:PhysicsPrice: Bought3
3) A 2-kg point-like (cannot rotate) object interacts with an unknown
source and the potential energy (P E) as a function of horizontal coordinate (x in meters) is given by the equation P E(x) = 1 4x4 6x3 + 46x2 120x. The graph of this function is shown beow. The object starts at x = 0.3 m with an initial speed of vi = 10 m s1, moving towards the right. The initial thermal energy of the object is 20 J. Once it is in the region 6 ? x ? 10 m, a braking mechanism kicks in and the thermal energy increases linearly as a function of x such that the object sits perfectly at rest at x = 10 m. The object interacts with this potential and the braking mechanism only. −1 0 1 2 3 4 5 6 7 8 9 10 11 12 13 x (m) −140 −120 −100 −80 −60 −40 −20 0 20 40 60 80 100 120 140 160 180 200 PE (J) PE vs x a.) During this motion, find the location where the object is traveling at its highest speed. Also calculate this speed. b.) Calculate the x-component of the interaction force (Fx) experienced by the object at x = 4 m. Specify both the magnitude and direction. c.) Sketch and label the graphs of kinetic energy (KE), thermal energy (Eth), and the total energy (Etot). Sketching means you have to show the important features of the curves such as minimum and maximum points (if any), and the approximate curvature. Label the minimum and maximum points (if any) on both the energy axis and the horizontal axis.
