question 2) You also watched a video by 3Blue1Brown about finding

Pythagorean triples using complex multiplication. That is, integers a, b, c for which a^2 + b^2 = c^2. If you remember, the idea is to start with any integers m, n, create the complex number p = m + in, and then calculate p^2 which will be a+bi. I would like you to 'create 'your own personal Pythagorean triple using m = number of letters in your first name and n = number of letters in your last name. Then check directly that a^2 + b^2 = c^2. 3Blue1Brown said that the hypotenuse c equals the absolute value of p squared, i.e. c = p(p) where p is the complex conjugate of p. Are they correct?

question 4 : Repeat Question 2 part (b) only, using the function u(x,y) = x^4 + y^4 - 6 x^2 y^2.
First name: 4
last name: 6

pur-new-sol

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