Given: g(x):R---->R is continuous g(0)=1 Show that if there exists a +ve no

Subject:MathPrice:2.84 Bought3

Share With

Given:

g(x):R---->R is continuous

g(0)=1

Show that if there exists a +ve no. 'a' where g is zero..i.e. g(a)=0, then there exists a smallest +ve no. 'k' where g(k)=0.

Hint: Consider the set of all positive x where g(x)=0

 

Note: This is the complete question,Concepts which may be used: Convergence of sequences and Continuity of a function.