Use the metal spatula to measure the calculated amount of Na2CO3 and carefully add it to the 25ml glass beaker. Submerge the weigh boat. Use the information and examples provided in the exploration to determine the maximum amount of CaCO3 in grams that can be produced from the precipitation reaction

The Percipitaion Reaction would be

Na₂CO₃ + CaCl₂ ----------> CaCO₃ + 2NaCl

6g of Na₂CO₃ is added to 25 ml beaker

Number of moles of Na₂CO₃ reacted=6/105.98=0.0566 moles

Number of moles of CaCO₃ formed=0.0566 moles (Based on the Equation)

Maximum amount of CaCO3 that can be formed from 6g of Na₂CO₃ = 0.0566x100=5.6g (Molar Mass of caCo3=100g)

Note:These value are based on a experiment conducted on a Sample.If you have conducted the experiment use those value instead.Or make changes if your instructor asks you to do

Hope you understood.Have a Great Day