question archive Find the? mean, variance, and standard deviation of the binomial distribution with the given values of n and p
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Find the? mean, variance, and standard deviation of the binomial distribution with the given values of n and p.
n equals 80?, p equals 0.5
The? mean, mu?, is
nothing. ?(Round to the nearest tenth as? needed.)
Find the? mean, variance, and standard deviation of the binomial distribution with the given values of n and p.
n equals 125?, p equals 0.75
The? mean, mu?, is
nothing. ?(Round to the nearest tenth as? needed.)
For Binomial distribution
Mean = ?μ? = np
Variance = ?σ2? = npq
Standard deviation = ?σ? = ?npq??
Step-by-step explanation
1) n = 80
p = 0.5
q = 1 - p = 1 - 0.5 = 0.5
Mean = ?μ? = np = 80x0.5 = 40
Variance = ?σ2? = npq = 80 x 0.5 x0.5 = 20
Standard deviation = ?σ? = ?npq?? = ?80(0.5)(0.5)?? = 4.47 = 4.5
2) n = 125
p = 0.75
q = 1 - p = 1 - 0.75 = 0.25
Mean = ?μ? = np = 125x0.75 = 93.75 = 93.8
Variance = ?σ2? = npq = 125 x 0.75 x0.25 = 23.4375 = 23.4
Standard deviation = ?σ? = ?npq?? = ?125(0.75)(0.25)?? = 4.84 = 4.8