question archive Suppose a computer contained 512MB (MiB) of main memory, and an operating system needed to create a virtual memory of twice that size using pages of 2KB (KiB)
Suppose a computer contained 512MB (MiB) of main memory, and an operating system needed to create a virtual memory of twice that size using pages of 2KB (KiB)
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Suppose a computer contained 512MB (MiB) of main memory, and an operating system needed to create a virtual memory of twice that size using pages of 2KB (KiB). How many pages would be required?
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Read the following left-to-right, which is different from the way that computer languages usually go, which is from the right side (an expression) to the left side (the variable to be assigned a value).
512MB x 2 = 1024MB
1024MB = 1024 X 1024 KB = 1048576KB
1048576KB / 2KB = 524288
