question archive The balanced equation is 5C2O4^2- + 16H^+ + 2 MnO4^- yields 10CO2 + 2Mn^2+ +8H2O
The balanced equation is 5C2O4^2- + 16H^+ + 2 MnO4^- yields 10CO2 + 2Mn^2+ +8H2O
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The balanced equation is 5C2O4^2- + 16H^+ + 2 MnO4^- yields 10CO2 + 2Mn^2+ +8H2O. Mass of Na2C2O4 is 0.278. Molar mass of Na2C2O4 is 134.00. Moles Na2C2O4 is 2.07x10^-3 . Volume of solution is 50.00 mL. Molarity of Na2C2O4 is 0.041 . Please calculate Part C with the given information for both trials. Use the average molarity from part b to determine the average molarity of unknown Na2C2O4 sample.
PartB
Trial 1 :
Final buret reading KMnO4: 22.10
Initial buret reading KMnO4: 0.30
Volume KMnO4 used: 21.80
Volume Na2C2O4 titrated: 10.00
Moles Na2C2O4 titrated: 4.10x10^-4
Moles KMnO4 used: 1.64 x10^-4
Molarity of KMnO4: 7.52 x10^-6
Trial 2 :
Final buret reading KMnO4: 23.75
Initial buret reading KMnO4: 2.10
Volume KMnO4 used: 21.65
Volume Na2C2O4 titrated: 10.00
Moles Na2C2O4 titrated: 4.10x10^-4
Moles KMnO4 used: 1.64x10^-4
Molarity of KMnO4: 7.58x10^-6
Average molarity of KMnO4: 7.55x10^-6
Part C:
Trial 1
Volume Na2C2O4: 10.00
Final Buret reading KMnO4 : 17.00
Initial buret reading KMnO4: 0.30
Volume (KMnO4) titrated:
Moles KMnO4 used:
Moles Na2C2O4 used:
Molarity of unknown Na2C2O4:
Trial 2:
Volume Na2C2O4: 10.00
Final Buret reading KMnO4 : 18.30
Initial buret reading KMnO4: 1.30
Volume (KMnO4) titrated:
Moles KMnO4 used:
Moles Na2C2O4 used:
Molarity of unknown Na2C2O4:
Average Molarity of unknown Na2C2O4:
