question archive The balanced equation is 5C2O4^2- + 16H^+ + 2 MnO4^- yields 10CO2 + 2Mn^2+ +8H2O

The balanced equation is 5C2O4^2- + 16H^+ + 2 MnO4^- yields 10CO2 + 2Mn^2+ +8H2O

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The balanced equation is 5C2O4^2- + 16H^+ + 2 MnO4^- yields 10CO2 + 2Mn^2+ +8H2O. Mass of Na2C2O4 is 0.278. Molar mass of Na2C2O4 is 134.00. Moles Na2C2O4 is 2.07x10^-3 . Volume of solution is 50.00 mL. Molarity of Na2C2O4 is 0.041 . Please calculate Part C with the given information for both trials. Use the average molarity from part b to determine the average molarity of unknown Na2C2O4 sample.

PartB

Trial 1 :

Final buret reading KMnO4: 22.10

Initial buret reading KMnO4: 0.30

Volume KMnO4 used: 21.80

Volume Na2C2O4 titrated: 10.00

Moles Na2C2O4 titrated: 4.10x10^-4

Moles KMnO4 used: 1.64 x10^-4

Molarity of KMnO4: 7.52 x10^-6

 

Trial 2 :

Final buret reading KMnO4: 23.75

Initial buret reading KMnO4: 2.10

Volume KMnO4 used: 21.65

Volume Na2C2O4 titrated: 10.00

Moles Na2C2O4 titrated: 4.10x10^-4

Moles KMnO4 used: 1.64x10^-4

Molarity of KMnO4: 7.58x10^-6

Average molarity of KMnO4: 7.55x10^-6

Part C:

Trial 1

Volume Na2C2O4: 10.00

Final Buret reading KMnO4 : 17.00

Initial buret reading KMnO4: 0.30

Volume (KMnO4) titrated:

Moles KMnO4 used:

Moles Na2C2O4 used:

Molarity of unknown Na2C2O4:

 

Trial 2:

Volume Na2C2O4: 10.00

Final Buret reading KMnO4 : 18.30

Initial buret reading KMnO4: 1.30

Volume (KMnO4) titrated:

Moles KMnO4 used:

Moles Na2C2O4 used:

Molarity of unknown Na2C2O4:

Average Molarity of unknown Na2C2O4:

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