XYZ Corp makes widgets. 1% of the widgets are defective. XYZ manufactures 100,000 widgets. The standard deviation for this binomial distribution is- (a)- (Round to two decimals.)

 

The answer is =31.46

Step-by-step explanation

Standard deviation (S) = √ (n*p*q)

Where

n=total population

p=probability of success

q=probability of failure=(1-p)

in the question,

n=100,000

p=1%=0.01

q=(1-0.01)=1-0.01=0.99

so putting about values in the formula

Standard deviation (S) = √ (n*p*q)

=√ (100,000 * 0.01 *0.99)

= √990

=31.46