Solution for QID #95002: Here are ##y=e^x## and ##y=1+x## on the same coordinate syst | StudyHelpMe

Here are ##y=e^x## and ##y=1+x## on the same coordinate system near ##0##. (You can scroll in or out and drag the graph around with a mouse.) graph{(y-e^x)(y-(1+x))=0 [-5.723, 6.763, -2.37, 3.873]} We can see that the curves are close to each other. To answer the second question we can graph the difference, ##y=e^x-(1+x)## and try to determine when ##y## is between ##-0.1## and ##0.1## graph{y=e^x-(1+x) [-1.085, 1.049, -0.406, 0.66]} I prefer to graph ##y = [e^x-(1+x)]-0.1## . The difference between ##e^x## and ##1+x## is less than ##0.1## when this ##y## is negative. So we just find the ##x## intercepts: approximately ##-0.483## and ##0.416## graph{y = e^x-(1+x)-0.1 [-1.923, 1.922, -0.959, 0.963]}