question archive The initial mass of the solution was 100g As 50% (w/w) was present in 100g solution , we can say the mass of the solute in initial solution was 50g After addition of x g solute in 100g solution the changed mass of solution became (x+100)g and total amount of solute became (x+50)g
The initial mass of the solution was 100g As 50% (w/w) was present in 100g solution , we can say the mass of the solute in initial solution was 50g After addition of x g solute in 100g solution the changed mass of solution became (x+100)g and total amount of solute became (x+50)g
Subject:ChemistryPrice: Bought3
The initial mass of the solution was 100g As 50% (w/w) was present in 100g solution , we can say the mass of the solute in initial solution was 50g
After addition of x g solute in 100g solution the changed mass of solution became (x+100)g and total amount of solute became (x+50)g. So the percentage of solute in final solution became 60%.
So
##(x+50)/(x+100)xx100=60##
##=>(x+50)/(x+100)=60/100=0.6##
##=>x+50=0.6(x+100)##
##=>x+50=0.6x+60##
##=>x-0.6x=60-50##
##=>0.4x=10##
##=>x=10/0.4=25##
