question archive A charged particle A exerts a force of 2
A charged particle A exerts a force of 2
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A charged particle A exerts a force of 2.62 MuN to the right on charged particle B when the particles are 13.7 mm apart. Particle B moves straight away from A to make the distance between them 15.6 mm What vector force does it then exert on 4?
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Answer:
F = KQq/r^2
so,
2.62 = KQq/13.7^2
Forcce = KQq/15.6^2
so,
dividing two equations gives-
Force = 2.62*13.7^2/15.6^2 = 2.021 micro N
