question archive Suppose that y is inversely proportional to x and that y = 72 when x = (a) Find the constant product for the relationship
Suppose that y is inversely proportional to x and that y = 72 when x = (a) Find the constant product for the relationship
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Suppose that y is inversely proportional to x and that y = 72 when x = (a) Find the constant product for the
relationship. (b) Find y when x = 8. (a) The constant product is (Simplify your answer. Type an integer or a
fraction.) (b) When x is 8, y is (Simplify your answer. Type an integer or a fraction.)
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Answers:
(a) proportionality constant is 24.
(b) y = 3 when x = 8.
Step-by-step explanation
Given that;
y is inversely proportional to x
Then ;
y=c(x1?) ----(i)
Where c is proportionality constant.
And given that y = 72 when x = 1/3
So from (i) we can write
72=c(31?1?)
= 72=3c
Therefore,
c = 24
So,
(a) proportionality constant is 24.
Now for (b);
We have to find value of y when x= 8.
So from (i) and c = 24
We can write
y=24(x1?)
y=24(81?)
Therefore y = 3 when x = 8.
