Develop a MATLAB program to create matrix MATH, considering the following: 11.5t ROW ELEMENTS:
lstterm— 1; last term — ll; spacing 2 2"" HOW ELEMENTS: 1|.?t term— CI: last term — 25: spacing 5 3"" HOW
ELEMENTS: il.St term— it); last term — ED; number of elements —6

Our MATA matrix generator function should be able to generate the following:

>> myMATAGen

ans =

     1     3     5     7     9    11
     0     5    10    15    20    25
    10     0     0     0     0    60

The following code would be able to achieve the result:

%****************************************************************************
%
% Function Name: myMATAGen()
% 
% Parameters: None
%
% Description: Generates a matrix with the following criteria:
%              1st Row Elements: 1st term - 1; last term - 11; spacing 2
%              2nd Row Elements: 1st term - 0; last term - 25; spacing 5
%              3rd Row Elements: 1st term - 10; last term - 60; number of
%              elements - 6.

function MATA = myMATAGen()
% Generate an initial function
MATA = zeros(3,6);   % Represents 3 Rows and 6 elements per row
MATA(1,:) = 1:2:11;
MATA(2,:) = 0:5:25;
MATA(3,1) = 10;
MATA(3,6) = 60;
end

Step-by-step explanation

Below is an explanation of each line of code of the MATA matrix generator program:

Line 1

MATA = zeros(3,6);   % Represents 3 Rows and 6 elements per row

• This is merely a means to generate a matrix of defined size, but with 0 as all elements.
  • 3 - represents the 3 rows needed.
  • 6 - represents 6 elements that would be put per row.
• Removing this line would still make the matrix generator work but is highly recommended to be included for memory purposes.

Line 2

MATA(1,:) = 1:2:11;

• This line of code generates the following portion of the matrix:
  • First Row Elements: 1st term - 1; last term - 11; spacing 2
• It used the MATLAB array generator with the following form:
  • h=j:i:k
  • Where:
    • j−firstelementofthearray
    • i−spacebetweenelementsofthearray
    • k−lastelementofthearray
  • Another way to express this is:
    • h=[j?j+1⋅i?j+2⋅i?...?j+fix(ik−j?)?]
    • Note: fix is rounding to the integer nearest to 0.
  • This form generates an array with elements conforming to the criteria of j, i, and k.
    • if with the given j(first element) and i(space between) you cannot get the exact k (last element), it will choose the value that is closest (not greater) to k.
• On the left side, MATA(1,:) means we are accessing the first row, all elements.
  • In general:   A(n,:)
    • Means: nth row, all elements of Matrix A.

Line 3

MATA(2,:) = 0:5:25;

• This line of code is for generating the Second Row.
• This uses the same principle of Line 2.
  • However, instead of MATA(1,:), we use MATA(2,:) to access the Second Row of the matrix.

Line 4

MATA(3,1) = 10;

• This line of code is for generating the 1st element of the 3rd row.
• The expression on the left MATA(3,1) means to access the element at the 3rd Row, 1st Column of the matrix.
  • Which could also be interpreted as the First Element of the Third Row.
• In this case, it is assigning 10 to that spot in the matrix.

Line 5

MATA(3,6) = 60;

• This line of code is for generating the last element of the 3rd row.
• This line shares similar principle to Line 4.
• Notice now that we have MATA(3,6) on the left.
  • This means we are assigning a value at the Third Row, 6th Column of the matrix.
  • We assume that the 6th column is the last because it is the total number of elements in that row.
    • Note: MATLAB follows a 1-start index (i.e. the first element has an index of 1).