The top of a swimming pool is at ground level. If the pool is 2.00 m deep, how far below ground level does the bottom of the pool appear to be located when (a) the pool is completely filled with water? (b) When it is filled halfway with water? 

Answer of the question as follows. 

Step-by-step explanation

Solution:

Girno . Actual depth h= 2m . Appearnt depth b'= ? solution : Firstly we knowo the retroactive index of water is 4 . For a > We know the condition, when observer in bases modium a object in denser medium then Formula Fer Refractive index is Real depth = Uld = R.J Denser appesent depth ya R. I Racer la = 1. Refractive index For aid Ud = Ulw = 4/2 R. J of water Here actual depth h= p= am (Real depth) :. Uws Real depth = P APP, depth =) 41 = P = 2 8 6 = 1.5 4 / 2 h' = 1 .5 m hi = 15 -: The ground level be appear at to be 1.5 m deep

6] water filled halfway ie Read depth P will change by 2m = Im 2 -. Now p = Im Again we use same to emula Un = Real depth = P app. depth =)h= P = 3 = 0. 75 m 4/ 3 4 h' = 075 m - 1 h = 0.75 The appesent depth of pool to be ofsm.

  In  given problem mentioned that depth of pool is 2m and water fully filled , that is depth pool is the real depth( p) of water and is equal to 2m. 

Now in question b clearly mentioned the the water halfway filled i.e real depth (p)  of water is  change by 2m/2 = 1m.