You are interested in finding a 95% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 12 randomly selected college students. Round answers to 3 decimal places where possible. 4761267102110111 a. To compute the confidence interval use a distribution. b. With 95% confidence the population mean number of days of class that college students miss is between C] and C] days. c. If many groups of 12 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About C] percent of these confidence intervals will contain the true population mean number of missed class days and about C] percent will not contain the true population mean number of missed class days. Hint: Hints El Video 5 [+1

Step 1: Determine which distribution is used. 

Step 2: Calculate the mean and standard deviation of a given data set. 

Step 3: Calculate the confidence interval.

Step-by-step explanation

STEP-18 Given Samplesize= 12 ( No. of days for 12 randomly selected . college students) If n> 30 use Z-distribution If n < 30 Use T- distribution use. 9).. To Compute the confidence interval use a t-distribution Confidence Interval formula Page Number 1 CI= set tocam x = mean of givendata s - standard deviationad given data STEP 2 8 n = sample size of givendata Given twelev data points 4, 7, 6, 12, 6 5 7, 10, 2, 1, 10, 11,1 mean ( x ) = 4 + 7 + 6 + 12 + 6 + 7 + 10 + 2 + 1 + 10 + 11 + 1 12 = 6-41666 = 6.42 = (6.417 ) .. Standard deviation (s ) = 3 ( x ; - 7 ) 2 n = 12 ap S = / ( 4 - 6- 4 2 ) 2 + (7 - 6. 4 2 ) 2+ ( 6 - 6.42 ) + ( 12 - 6.43) + (6-6.42)+ (7 - 6- 42 ) + ( 10- 6.42 ) + ( 2- 6.42 ) + 6-64212 (10- 6:42 ) + (11-6.42) + (1 - 6.4 2 12 11 16 2 . 91667 F 1 1 ( 14 - 81 060 6 5 3. 848 4 S 308 #4 8

STEP- 3: CIS 6.417 I tscoreas% 3-848 12 degreeof freedom ( n-1) = (12-7 ) = 11 tscore for de= 11 at 95%. Page Number 2 for right tailed tsauce( as soon) 1.7 9588 CI S 60 417 + ( 1 7 8 9 588 ) 3.848 CIs 6:417 + 6- 886 33 3-46410 7 4.4290 - 5 days - 6.417 7 1- 98 791 8-404 9 = 9 days 14 . 42 90 to 8. 404 9 laverlimit upper limit As half day notpossible (3 days to 9 days ) by with 95% confidence the population mean number of days of class that college students miss between 5 and 9 day's () If many group of 12 randomly selected non resident college students are surveyed, then. a different confidence interval would be produced from each group. About 95 percent of these confidence intervals will contain the true Population mean number of missed class days and about (100-95)= 5% will not contain the true population, mean numberof missed class days