question archive Knowledge Check on Molality ! Direction: Solve the given problem

Knowledge Check on Molality ! Direction: Solve the given problem

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Knowledge Check on Molality ! Direction: Solve the given problem. You may use a separate sheet
of paper. How many grams of solute is present in 0.4 moles Magnesium hydroxide, Mg(OH], in 550 g water ,
H. 0? The molar mass of Me(OH), is 58 g/ mol . Given : Solution :

used the fraction term

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Grams of solute in 0.4 moles of Mg(OH)2 in 550 g of H2O = 23.2 g

Step-by-step explanation

Given;

Moles of solute (Mg(OH)2) = 0.4 mol

Molar mass of Mg(OH)2 = 58 g/mol

Mass of the solute (Mg(OH)2) = ?

Solution

Mass = moles*molar mass

Mass of the solute (Mg(OH)2) = 0.4 mol*58 g/mol

Mass of the solute (Mg(OH)2) = 23.2 g

So,

Grams of solute in 0.4 moles of Mg(OH)2 in 550 g of H2O = 23.2 g

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