question archive A string that passes over a pulley has a 0
A string that passes over a pulley has a 0
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A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.655 kg mass attached to the other end. The pulley, which is a disk of radius 9.50 cm, has friction in its axle. What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium? (Answer should be in N m)
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Answer:
Given that the masses are m1 = 0.341 kg and m2 = 0.655 kg
Radius of pulley is r = 9.50 cm = 0.09 m
If the system is in equilibrium tension the the each stringis
T1 = m1*g = 3.34N
and T2 = m2*g = 6.419 N
Then the torque is τ =T2*r - T1*r
= ( T2 - T1 ) r
= 0.292 N.m
