in a stream of glycerine in motion at a certain point the velocity gradient is 0.25m/s/m the mass density of fluid is 1268.4 kg per.cubic meter and kinematic viscosity is 6.30 × 10^(-4) square meter per second calculatethe shear stress at the point

 

Answer:

?τ=0.199773Pa??

Step-by-step explanation

Follow the steps for better understanding,

? Write down the formula for shear stress,

 τ=μdu/dy

 where, 

τ, shear stress, 

μ,dynamic viscosity, 

du/dy?, velocity gradient, ?

Write down the given data,

?du/dy?=0.25 in ms^−1 per m,

ρ=1268.4kg/m3

?ν=6.30×10^−4m^2 per sec,?

? Write down the certain relation between density, dynamics and kinematic viscosity

 μ=ρ×ν?

? After substituting the certain relation we get, 

τ=(ρ×ν)du/dy??

? Substitute the numerical values, τ=(1268.4×6.30×10^−4)0.25τ=0.199773Pa?