question archive My daughter is into making balloon animals
My daughter is into making balloon animals
Subject:ChemistryPrice:4.89 Bought3
My daughter is into making balloon animals. Suppose I took one of her twisty balloons and filled it with 100.0 grams of helium. I took a second one and I blew 100.0 grams of my own air into it. Assume that the composition of air in the second balloon was such that it contained 78.0 grams of nitrogen, 20.0 grams of oxygen, 1.0 gram of water (vapor), 0.97 grams of argon, and 0.03 grams of carbon dioxide. Which of the following statements would be true if I were to count all of the individual atoms in each balloon?
- A. This scenario cannot happen because gases have no mass.
- B. There are more total atoms in the helium balloon
- C. There are more total atoms in the balloon containing regular air
- D. Each balloon has an equal number of atoms.
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molar mass of He gas = 4 g/mol
then 100 g of He = ?4100?? = 25 mol of He gas in first balloon
now coming to the second balloon
molar mass of nitrogen gas = 28 g/mol
78 g of nitrogen gas = ?2878?? = 2.785 mol
molar mass of oxygen gas = 32 g/mol
20g of oxygen gas = 0.625 mol
molar mass of water vapor = 18 g/mol
1.0g of water vapor = ?181?? = 0.0556 mol
molar mass of argon = 40 g/mol
0.97g of argon = ?400.97?? = 0.0243 mol
molar mass of carbon dioxide = 44 g/mol
0.03g of carbon dioxide = ?440.03?? = ?6.81∗10−4? mol
so the total number of moles of gases = 2.785 + 0.625 + 0.0556 + 0.0243 + ?6.81∗10−4? = 3.49 mol
thus from the above calculation we can see that (B) There are more atoms in the helium balloon (Answer)
higher number of moles = higher number of atoms
