question archive Given the following equation for the reaction of Ryersonite oxide with water: H2O(g) + RyO(g) → H2(g) + RyO2(g)ΔG°rxn = -28

Given the following equation for the reaction of Ryersonite oxide with water: H2O(g) + RyO(g) → H2(g) + RyO2(g)ΔG°rxn = -28

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Given the following equation for the reaction of Ryersonite oxide with water: H2O(g) + RyO(g) → H2(g) + RyO2(g)ΔG°rxn = -28.6 kJ

Calculate ΔG°rxn for the reaction.

6 H2O(g) + 6 RyO(g) → 6 H2(g) + 6 RyO2(g)

A) -4.77 kJ

B) +171.6 kJ

C) -171.6 kJ

D) +4.77 kJ

E) -28.6 kJ

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