question archive Given the following equation for the reaction of Ryersonite oxide with water: H2O(g) + RyO(g) → H2(g) + RyO2(g)ΔG°rxn = -28
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Given the following equation for the reaction of Ryersonite oxide with water: H2O(g) + RyO(g) → H2(g) + RyO2(g)ΔG°rxn = -28.6 kJ
Calculate ΔG°rxn for the reaction.
6 H2O(g) + 6 RyO(g) → 6 H2(g) + 6 RyO2(g)
A) -4.77 kJ
B) +171.6 kJ
C) -171.6 kJ
D) +4.77 kJ
E) -28.6 kJ